Figuring out how much electricity your tank uses?

stdreb27

Active Member
So how does this work the wattage on the pump is per hour or day, for instance my mag 9.5 says it uses 93 watts but it doesn't specify over what period of time. Can I assume per hr?
 
C

cmaxwell39

Guest
Watts is how much power it draws. A watt is the voltage of the motor times the amount of amps it draws. What you pay for from the electric company are killowatt/hours. Your mag 9.5 running for one hour would draw .093 kwh of electricity. So over a 24 hr period it draws 2.23 kwh.
If you wanted to figure out how much electricity your tank was drawing you would take the watts of each piece of equipment and divide it by 1000 to get killowatts. Then you would multiply the killowatts by the number of hours everyday that said eqipment was running. Once you add up all your equipment you would have a daily draw for your tank. You could then multiply it by 30 to get monthly draws if you wanted too. HTH.
 

stdreb27

Active Member
So
93 mW / H *24 HR / Day * 31 Day / Mo = 98022 mW per day
98022 mW * 1 KWh/1000 mWH= monthly electrical usage?
Then multiply that times the kilowatt usage and you have how much you pay?
 
C

cmaxwell39

Guest
Close.
1 KW(Killowatt)=1000 w (watts)
So 93w=.093KW (93/1000)
.093KWx24hrx31=98.022kwh (killowatt hours)
Electric company rate per kwh x 98.022 = cost per month to run this pump.
As a little bit of clarification. The pump draws 93w weather it runs for 6 days or 2 min. However we buy killowatt hours from the power company. 1 kwh=1kw of electricity being used for one hours time. Watts is simply a measure of the energy that it takes to run the pump. You have to add in time to the equation in order to have a way to quantify the amount of electricity being used.
 

stdreb27

Active Member
Originally Posted by cmaxwell39
http:///forum/post/2704491
Close.
1 KW(Killowatt)=1000 w (watts)
So 93w=.093KW (93/1000)
.093KWx24hrx31=98.022kwh (killowatt hours)
Electric company rate per kwh x 98.022 = cost per month to run this pump.
As a little bit of clarification. The pump draws 93w weather it runs for 6 days or 2 min. However we buy killowatt hours from the power company. 1 kwh=1kw of electricity being used for one hours time. Watts is simply a measure of the energy that it takes to run the pump. You have to add in time to the equation in order to have a way to quantify the amount of electricity being used.
Well if 1 kwh=1kw then mathimatically The pump draws 93w weather it runs for 6 days or 2 min.
Doesn't matter.
That means that that friggen mag 9 is 10% of my electricity bill!
 

rushprop

Member
If the mag is 10% of your bill, then i would guess the rest of the tank is the other 90%.
Better start erecting your windmill now.
 

schnutzzy

Member
Before I set up my 72 my electric bill was 35 a month. Now with all the stuff I run including 2x250's MH I pay 135 a month. Ouch!!!!!!
 

mr_x

Active Member
umm...an extra hundred a month. that's all i care about..the bottom line.
i have a 300 gallon tv system and a 65 gallon tv system running to get the extra hundred.
 

stdreb27

Active Member
Originally Posted by Mr_X
http:///forum/post/2705177
umm...an extra hundred a month. that's all i care about..the bottom line.
i have a 300 gallon tv system and a 65 gallon tv system running to get the extra hundred.
lol well with 2 mag 9's running 24-7 lights running 8 hrs and a couple powerheads I'm looking at around 40 bucks. BLA
 
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