help please...

camanuch

Member
anyone god in math??
here is where i am developing my tank and stand. here is where i need your help.

any and all help will be greatly appreciated
 

spanko

Active Member
Why do you need the angles? If you draw the right angles with a square to ensur they are 90 degress the measurements will develop the angles.
You can also get a protractor from just about any store and measure the angles.
As you can see I don't know the equation for this.
 

camanuch

Member
im not worried ablout the right angles. the other two angles are the ones im worried about. i have to bevel the edge at the right degree so that it is flush when sealing and gluing.
 

gmann1139

Active Member
No, its not going to be 135.
Camanuch, you're defying Pythagoras and the laws of physics here. I'm not sure where you got 32" from, but its not right.
If you are set on a 24" square, with the corner cut out, your measurements will be:
Top & Right - 24"
Bottom & Left - 8"
Diagonal - 22.625" (see below)
That would mean that the diagonal piece (on both sides) and the 8" pieces (on one side only) would have to be beveled at a 67.5 degree angle (1/2 of 135). That will create an 'equal' joint at those two corners, assuming the pieces of glass are the same thickness.
Ok, now back to the diagonal piece's length:
The corner you are cutting off the tank is 16" by 16" (24" - 8"). Since those two pieces are at right angle, the length of the diagonal (hypotenuse) will be the square root of the sum of the squares of the other two sides.
16"^2 + 16"^2 = x ^2
If you have Excel, its:
=SQRT(16^2+16^2)
That comes out to be 22.627, which is 22 and 5/8".
 

camanuch

Member
whouldnt both 8" pieces have to be beveled to fit the front piece of acrylic?
32 was just amade up number and i ment to put in 23. so both (b, and a) dont need to be beveled
 

camanuch

Member
disregard last post. i reread and i understand. so both sides of the 22 5/8 front piece will be beveled at 67.5* And then the two pieces at 8" will be beveled at 67.5* one one side. i got it thanks to all who helped out. now that will be the same angle for the stand as well correct?
 

camanuch

Member
also gmann can you also give me the formulia for volume.
i want it to about 50 gal or some where around there.
 

gmann1139

Active Member
Why do you think I'll have the formula for volume?
Ok, here goes:
Your outside area is going to be 24" x 24", minus the cutout of .5*(16" x 16"), which equals 448 square inches.
Its actually going to be slightly less due to the thickness of the glass, but this is close enough for an estimate.
Based on 231 cubic inches = 1 gallon, for each inch of height, you'll gain 448/231 = 1.94 gallons, which I'd round down to 1.9 for the 'glass loss.'
So if you want 50 gallons, you're going to have to go at least 26" tall (50/1.9). Add an inch or two for the fact the tank won't be full to the rim and you'll have a piece of glass on the bottom.
24", which might be easier to buy, minus 1" for top and bottom, would give you ~43 gallons, which isn't much less.
 
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