OMG!... The days shorter...

pezenfuego

pezenfuego

Active Member
I love math.
Did you know that the calendar (Gregorian) repeats itself every 28 years?
So March 3rd, 2038 will be a Wednesday. Snazzy huh? That's because there are 7 days a week and leap years occur every 4 years. Four times seven is 28.
You can give me any date (after 1752) and I can give you the day of the week in 30 seconds or less. Unfortunately this isn't very impressive over the internet.
Anyway, how does this relate to the thread?
Who cares it's in the aquarium forum.
You should google how to do that. It makes for a good party trick AND it is actually quite useful.
 
pezenfuego

pezenfuego

Active Member
Originally Posted by Hunt
http:///forum/post/3239301
show off

It's seriously is incredibly easy. It's worth the five minute to learn. If someone asks me to do something on said day, I can determine whether or not I have school that day and can help. It's pretty handy.
 
oceankid

oceankid

Member
Originally Posted by PEZenfuego
http:///forum/post/3239212
I love math.
Did you know that the calendar (Gregorian) repeats itself every 28 years?
So March 3rd, 2038 will be a Wednesday. Snazzy huh? That's because there are 7 days a week and leap years occur every 4 years. Four times seven is 28.
You can give me any date (after 1752) and I can give you the day of the week in 30 seconds or less. Unfortunately this isn't very impressive over the internet.
Anyway, how does this relate to the thread?
Who cares it's in the aquarium forum.
You should google how to do that. It makes for a good party trick AND it is actually quite useful.
Yes I know it!
2010's calendar is the same on 2021, 2027, 2038, 2049, 2055, 2066, 2077, 2083, 2094,
 
pezenfuego

pezenfuego

Active Member
Originally Posted by OceanKid
http:///forum/post/3239683
Yes I know it!
2010's calendar is the same on 2021, 2027, 2038, 2049, 2055, 2066, 2077, 2083, 2094,

You have to find yearly values. For years in the 21st century, it's easy.
Take the last two digits and divide by 4, then drop everything after the decimal. Take the resulting number and add it to the two digits. Then subtract 7 until it can no longer be subtracted. To make things easier, you can find the nearest multiple of 4 that is less than that number and then divide by four.
EX: 2010
10
10 is closest to 8
8/4=2
10+2=12
12-7=5
2010 is value 5. Any other year with value 5 has a repeating calendar. (Leap years mess this up.) For years in the 1900s, add 1. For years in 2100s, subtract 2 (or add 5 hehe).
So let's look at 2021
21
21 is closest to 20
20/4=5
21+5=26
26-7-7-7=5
2021 has a value of 5
Next up, 2027.
27
27 is closest to 24
24/4=6
27+6=33
33-7(4)
33-28=5
So 2027 has a value of 5.
Fun stuff, this math.
 
oceankid

oceankid

Member
Originally Posted by PEZenfuego
http:///forum/post/3239701
You have to find yearly values. For years in the 21st century, it's easy.
Take the last two digits and divide by 4, then drop everything after the decimal. Take the resulting number and add it to the two digits. Then subtract 7 until it can no longer be subtracted. To make things easier, you can find the nearest multiple of 4 that is less than that number and then divide by four.
EX: 2010
10
10 is closest to 8
8/4=2
10+2=12
12-7=5
2010 is value 5. Any other year with value 5 has a repeating calendar. (Leap years mess this up.) For years in the 1900s, add 1. For years in 2100s, subtract 2 (or add 5 hehe).
So let's look at 2021
21
21 is closest to 20
20/4=5
21+5=26
26-7-7-7=5
2021 has a value of 5
Next up, 2027.
27
27 is closest to 24
24/4=6
27+6=33
33-7(4)
33-28=5
So 2027 has a value of 5.
Fun stuff, this math.
I'm not really good in math!
 
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