NaHCO3 --> Na+ + HCO3-
HCO3- + H20 ? H2CO3 + OH-
H2CO3 (aq) ? dden="false"
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]-->H2O (l) + CO2 (g) the warmer the solution, the less CO2 is soluble so it eventually finds its way out
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We can add everything from the left of the three equation together and do the same with the right of the three equations to get:
NaHCO3 + HCO3- + H20 + H2CO3 --> Na+ + HCO3- + H2CO3 +OH- + H20 + CO2
And then cross of the products and reactants that are the same to end up ultimately with:
NaHCO3 --> Na+ + CO2 + OH-
Doing so is for the purpose of simplification, this equation is not something that would happen all at once, but in the above three steps.
As the [NaHCO3] increases so does [OH-] and we all know that as [OH-] increases, the pOH decreases which gives us a more basic solution.
Just in case you were wondering how that baking soda worked its magic.